Houjun Liu

additive inverse is unique in a vector space

Take a vector \(v \in V\) and additive inverses \(a,b \in V\).

\begin{equation} a+0 = a \end{equation}

defn. of additive identity

\begin{equation} a+(v+b) = a \end{equation}

defn. of additive inverse

\begin{equation} (a+v)+b = a \end{equation}

associativity

\begin{equation} 0+b = a \end{equation}

defn. of additive inverse

\begin{equation} b=a\ \blacksquare \end{equation}