A capacitor changes, then resists being charged further. Their rules work opposite to resistors.
capacitor in series
\begin{equation} \frac{1}{C_{eq}} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} \end{equation}
and yet,
capacitor in parallel
\begin{equation} C_{eq} = C_1 + C_2 + C_3 \end{equation}
energy stored by a capacitor
\begin{equation} E = \frac{1}{2} CV^{2} \end{equation}
where, \(E\) is the energy stored, \(C\) the capacitance, and \(V\) the voltage across the capacitor.
Which, subbing the formula below:
\begin{equation} U = \frac{1}{2} \frac{Q^{2}}{C} \end{equation}
voltage across and max charge stored on a capacitor
\begin{equation} C = \frac{Q}{V} \end{equation}
where, \(Q\) is the change and \(V\) the voltage
“the more change the capacitor can store given a voltage, the higher the capacitance.”
\begin{equation} Q = CV \end{equation}