Double Envelope Problem
Last edited: August 8, 2025One envelope has 10 times the money in the other money.
WLOG let \(x\) be the envelope in Cary’s hand. The money in \(y\), then, \(y = \frac{1}{2}\qty(\frac{1}{10}x)+\frac{1}{2}\qty (10x) = 0.05x+5x = 5.05x\). Wat.
Basically; regardless if Cary took the envelope \(x\) or \(y\), the other envelope is expected to have \(5\times\) more money. What.
Why?
There’s a bug in this:
\begin{equation} y = \frac{1}{2}\qty(\frac{1}{10}x)+\frac{1}{2}\qty (10x) \end{equation}
is not true! There is a human PRIOR BELIEF!! Its very unlikely that mykel/chris put 10000 dollars into an envelope; so each individual amount in an envelope has an exogenous probability of it happening!
Double Progressive Widening
Last edited: August 8, 2025double slit experiment
Last edited: August 8, 2025DPYD
Last edited: August 8, 2025A human gene similar to the gene PreTA found in E. Coli, a bacterial found in microbiome. See effects of PreTA on Fluoropyrimidine, and by proxy Capecitabmine for implications on cancer treatment.
