orthonormal basis
Last edited: August 8, 2025An Orthonormal basis is defined as a basis of a finite-dimensional vector space that’s orthonormal.
Additional Information
orthonormal list of the right length is a basis
An orthonormal list is linearly independent, and linearly independent list of length dim V are a basis of V. \(\blacksquare\)
Writing a vector as a linear combination of orthonormal basis
According to Axler, this result is why there’s so much hoopla about orthonormal basis.
Result and Motivation
For any basis of \(V\), and a vector \(v \in V\), we by basis spanning have:
OTC Markets
Last edited: August 8, 2025The OTC Markets/pink sheets are an unregulated group of Financial Markets, where many of the Penny stocks are.
Outcome Uncertainty
Last edited: August 8, 2025action outcomes are uncertain
P vs. NP
Last edited: August 8, 2025Polynomial Time \(P\) vs Non-Polynomial Time \(NP\)
- \(P\) are the problems that can be efficiently solved
- \(NP\) are the problems where proposed solutions can be efficiently verified
so! is \(P=NP\)?
If this is true, there are some consequences:
- proving can be automated
- cryptography would be able to be automated easily
anywhere there is a problem can be globally optimized. This is too good to be true, so probably \(P \neq NP\).
p(T)
Last edited: August 8, 2025We can use the scalars of a polynomial to build a new operator, which scales copies of an operator with the coefficients \(a_{j}\) of the polynomial.
constituents
- \(p(z) = a_{0} + a_{1}z + a_{2}z^{2} + \cdots + a_{m}z^{m}\), a polynomial for \(z \in \mathbb{F}\)
- \(T \in \mathcal{L}(V)\)
requirements
\(p(T)\) is an operator refined by:
\begin{equation} p(T) = a_{0} I + a_{1} T + a_{2} T^{2} + \cdots + a_{m} T^{m} \end{equation}
where, \(T^{m}\) is the power of operator
