SU-CS242 OCT032024
Last edited: August 8, 2025Lambda Calculus
Like SKI Calculus, its a language of functions; unlike SKI Calculus, there are variables.
\begin{equation} e\to x \mid \lambda x.e \mid ee \mid (e) \end{equation}
meaning, we have:
- a variable \(x\)
- an abstraction \(\lambda x . e\) (a function definition)
- an application \(e_1 e_2\)
we call \((\lambda x . e)e’\) (a function and its argument, ready for reduction) a redex
.
abstraction
def f(x) = e
can be written as:
\begin{equation} \lambda x.e \end{equation}
SU-CS242 OCT082024
Last edited: August 8, 2025hyperstrict
aggressively reduce everything
call-by-value
we recursively evaluate the argument before reducing the function application
implementing lambda calculus
we can implement Lambda Calculus through abstracting it into SKI Calculus:
observe that \(\lambda x.e \implies A(E, x)\); for each expression \(e\), we replace the innermost lambda expression \(\lambda x.e’\) in \(e\) by \(A(e’, x)\).
simply typed Lambda Calculus
Recall normal lambda calculus:
\begin{equation} e \to x | \lambda x.e | e e \end{equation}
SU-CS242 OCT102024
Last edited: August 8, 2025more on types
Remember: when we say \(e: t\), this means that as we evaluate \(e\), after all reductions we will get a thing of type \(t\).
type checking
- start at the leaves, integers and variables
- for each one above, match the expression to the type rules
a* type inference
- for every distinct lambda variable, we name a new type
- then, for function applications, we have then also substitute the output type of the function with a type variable
then, to saturating the constraint, we solve them using:
SU-CS242 OCT152024
Last edited: August 8, 2025Lambda Calculus, review
Grammar:
\begin{equation} e \to (x | \lambda x.e | e e) \end{equation}
and beta reductions:
\begin{equation} (\lambda x . e_1) e_2 \to e_1 [x := e_2] \end{equation}
structural operational semantics
“why can’t we have logical rules to explain how programs execute?”
bold
type judgment
\begin{equation} A \vdash e :t \end{equation}
“under environment \(A\) for the free variables of \(e\), the entirety of \(e\) has type \(t\)”
value judgment
\begin{equation} E \vdash e \to v \end{equation}
SU-CS242 OCT172024
Last edited: August 8, 2025Lambda calculus, now with sums:
\begin{equation} e \to (x | \lambda \lambda x.e | e e | i | e+e) \end{equation}
explicit evaluation order
write \(e + e’\) as….
\(( \lambda x . ((\lambda y . (\lambda z.z) (x + y)) e’)) e\)
in a call by value world, this would explicitly specify the order that we add \(x\) and \(y\) together.
Notice! We can also write this with let notation: