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SU-ENGR76 MAY302024

Last edited: August 8, 2025

Consider a mapping between \(X \in \{0,1\}\), and output \(Y \in \{0,1\}\), with a chance of error of probability \(p\). So we have four outcomes:

XYp
001-p
111-p
01p
10p

Writing this out:

  • \(P(y=1|x=0) = p\)
  • \(P(y=0|x=1) = p\)
  • \(P(y=0|x=0) = 1-p\)
  • \(P(y=1|x=1) = 1-p\)

Recall chain rule:

\begin{equation} P(X,Y|A) = P(X|Y,A) P(Y|A) \end{equation}


Consider some input output pair:

\begin{equation} p(y=10 | x = 00) = p(y_1=1 | x_1=0, x_2=0)p(y_2=0| y_1=1, x_1=0, x_2=0) \end{equation}

SU-MATH109 Problem Set 1

Last edited: August 8, 2025

SU-MATH109 SEP272023

Last edited: August 8, 2025

Key Sequence

New Definitions

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Questions for Jana

  • Why does something being prime require that \(p>1\). that is, why is \(1\) not defined as prime?

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